1 . A 12 g bullet traveling at 520 m/s strikes a 1.2 kg block of wood that is ba
ID: 1283679 • Letter: 1
Question
1. A 12 g bullet traveling at 520 m/s strikes a 1.2 kg block of wood that is balanced on a table edge 0.6 m above ground (see figure). If the bullet buries itself in the block, find the distance D at which the block hits the floor. m
2. An 20 g rifle bullet traveling 290 m/s buries itself in a 4.6 kg pendulum hanging on a 3.4 m long string, which makes the pendulum swing upward in an arc. Determine the maximum vertical displacement of the pendulum (height).(g = 9.8 m/s2) meters
1. A 12 g bullet traveling at 520 m/s strikes a 1.2 kg block of wood that is balanced on a table edge 0.6 m above ground (see figure). If the bullet buries itself in the block, find the distance D at which the block hits the floor. m 2. An 20 g rifle bullet traveling 290 m/s buries itself in a 4.6 kg pendulum hanging on a 3.4 m long string, which makes the pendulum swing upward in an arc. Determine the maximum vertical displacement of the pendulum (height).(g = 9.8 m/s2) metersExplanation / Answer
1.
form momentum conservation on block -bullet ,
0.012 x 520 = (1.2 +0.012)u
u =5.15 m/s
now in vertical
h = ut + gt^2 /2
0.6 = 0 + 9.8t^2 /2
t = 0.35 sec
D = ut = 1.80 m
2.
from momentum conservation on bullet-pendulum ,
0.020 x 290 = (4.6 +0.020)u
u = 1.26 m/s
now for work energy theorem,
mgh= mv^2 /2
h = v^2 /2g = 0.080 m or 8 cm
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