a) The effective coefficient of kinetic friction is 0.360. Calculate the force e

Question

a) The effective coefficient of kinetic friction is 0.360. Calculate the force exerted by the man.

b) Calculate the work done by the man on the piano.

c) Calculate the work done by the friction force.

d) Calculate the work done by the force of gravity.

e) Calculate the net work done on the piano.

I need all correct answers in order to give full rating.

A 280kg piano slides 4.38m down a 31.2o incline and is kept from accelerating by a man who is pushing back on it parallel to the incline, as seen in figure below. a) The effective coefficient of kinetic friction is 0.360. Calculate the force exerted by the man. b) Calculate the work done by the man on the piano. c) Calculate the work done by the friction force. d) Calculate the work done by the force of gravity. e) Calculate the net work done on the piano. I need all correct answers in order to give full rating.

Explanation / Answer

a) F + umgcos(31.2) = mgsin(31.2)

F= mg ( sin (31.2) - 0.36 cos( 31.2) )= 576.5 N

b) Wman= - 576.5 * 4.38 = - 2525.07 J

c) Wfriction = - umgcos(31.2)* 4.38 = - 3700.93 J

d) Wgravity = mgsin(31.2) * 4.38 = 6226.02 J

e) Net work done is zero as there is no force acting in net on the piano

Thanks

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.