You are given a 9V battery and two resitors. The first resistor has a value of R

Question

You are given a 9V battery and two resitors. The first resistor has a value of R1 = 71 and the second has a value of R2 = 53 . If the two resistors are placed in parallel and connected to the battery...

a) What is the equivalent resistance of the circuit?

b) What is the value of the voltage across resistor R1? V

c) What is the value of the voltage across resistor R2? V

d) What is the value of the current through the resistor R1? A

e) What is the value of the current through the resistor R2? A

f) What is the value of the voltage across the battery? V

g) What is the value of the current through the battery? A

Explanation / Answer

A) Resistors in parallel is given by
1/R= 1/R1 + 1/R2
So R= 30.35 ohm
B) See voltage is the same across both resistors for a paralllel connection
so Answer is 9v
C)Same as Above =9V
D) Here the current in the circuit gets divided among the 2 resistors depending on the Resisitance value
so I(R1)= 9/71
I(R2)= 9/53
F) Across the battery the voltage is 9v

G) The current through battery is PD/Equivalent Resitance=9V/35.35

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