What is the equivalent Resistance for these three circuits, then power for the l

Question

What is the equivalent Resistance for these three circuits, then power for the last one? I got them wrong :-(

Accepted characters: numbers, decimal point markers (period or comma), sign indicators (-), notation). For scientific notation, a period MUST be used as the decimal point marker. Complex numbers should be in the form (a + bi) where "a" and "b" need to have explicitly st For example: {1+1i} is valid whereas {1+i} is not. {0-+-9i} is valid whereas {9i} is not. Find the equivalent resistance seen by the source. REq = 33.3K W R1 = 95275 Ohms (Ohms) R2 = 532001 Ohms (Ohms) R3 = 36763 Ohms (Ohms) Find the equivalent resistance REq. REq = 558528 Ohms (Ohms) Accepted characters: numbers, decimal point markers (period or comma), sign indicators (-), spaces (e.g., as thousand notation). For scientific notation, a period MUST be used as the decimal point marker. Complex numbers should be in the form (a + bi) where "a" and "b" need to have explicitly stated values. For example: {1+1i} is valid whereas {1+i} is not. {0+9i} is valid whereas {9i} is not. Find the equivalent resistance Rab and the power delivered by the source. Rab = 24.81 W P48V = Watts

Explanation / Answer

1.

200 and 50 are in parallel

200*50/(200+50) =40 kohms

40 and 20 are in series

40+20=60kohms

60 and 60 kohms are in parallel

60*60/(60+60)=30 kohms

30 and 30 kohms are in parallel ,so equivalent reistance

Req=30*30/(30+30)=15 kohms

2.

R2 and R3 are in series

R_23=532001+36763 =568,764 ohms

R1 and R_23 are in parallel ,so equivalent resistance

Req=95275*568,764/(95275+568764) =81605.1 ohms

3.

9 and 6 are in series

9+6 =15 ohms

15 and7.5 ohms are in parallel

15*7.5/(15+7.5) =5 ohms

5 and 2.5 are in parallel

5*2.5/(5+2.5) =1.67 ohms

1.67 and 5 ohms are in parallel

1.67*5/(5+1.67)=1.25 ohms

1.25 and 7 ohms are in series

1.25+7=8.25 ohms

8.25 and 8 are in parallel

8.25*8/(8.25+8)=4.06

6,2 and 4.06 are in series ,so equivalent resistance

Req=6+2+4.06 =12.06 ohms

b)

Power delivered

P=V2/Req=48^2/12.06

P=191.02 Watts

Related Questions

Navigate

• Browse (All)
• Browse W
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.