PHYS HELP Consider the charge versus voltage graph of a capacitor given below ta
ID: 1272208 • Letter: P
Question
PHYS HELP
Consider the charge versus voltage graph of a capacitor given below table. Calculate the capacitance of this capacitor from the charge vs voltage graph. If the actual capacitance is 2 mu F, find the percentage difference between the actual and experimental value. Figure below shows a 10 cm-diameter loop in three different magnetic fields. The loop's resistance is 0.11 Ohm . For each case, determine the induced potential difference, the induced current, and the direction of the current.Explanation / Answer
A. apply Capacitance C = Q/V
C = -1/-0.49
C = 2.04 uC
% error = 4%
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induced emf e = NAdB/dt
e = 1* 3.14* 0.05 *0.05* 0.5
emf e =3.925 mVolts
induced cuurent i = emf./R = 3.925/0.11 = 0.03568 Amps
direction is clockwise
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induced emf e = NAdB/dt
e = 1* 3.14* 0.05 *0.05* 0.5
emf e =3.925 mVolts
induced cuurent i = emf./R = 3.925/0.11 = 0.03568 Amps
direction is counter clockwise
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induced emf e = NAdB/dt or lvB
as tthere is no area providede, we may consider emf = 0
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