A converging lens is placed very far away from an object, so that an image is cr

Question

A converging lens is placed very far away from an object, so that an image is created very near the focal point of the lens. The image is real, smaller than the object, and inverted. As you move the lens closer to the object, (a) does the image get farther away from the lens, or closer to it? (b) Does the image get larger or smaller? When the lens reaches a distance of twice the focal length from the object, (c) where is the image located? (d) What is the nature of the image at this point?

C: 1) Infinity, 2) At the focal point, 3) At twice the focal length, or 4) At half the focal length
D: 1) No image (rays refract parallel), 2) Real (larger than the object, inverted), 3) Real (equal size as the object, inverted), or 4) Virtual (equal size, upright)
A converging lens is placed very far away from an object, so that an image is created very near the focal point of the lens. The image is real, smaller than the object, and inverted. As you move the lens closer to the object, (a) does the image get farther away from the lens, or closer to it? (b) Does the image get larger or smaller? When the lens reaches a distance of twice the focal length from the object, (c) where is the image located? (d) What is the nature of the image at this point?

C: 1) Infinity, 2) At the focal point, 3) At twice the focal length, or 4) At half the focal length
D: 1) No image (rays refract parallel), 2) Real (larger than the object, inverted), 3) Real (equal size as the object, inverted), or 4) Virtual (equal size, upright)

Explanation / Answer

a) farther

(b) larger

1/s + 1/s' = 1/f

1/2f + 1/s' = 1/f

c) s' = 2f...........3) At twice the focal length

d) M =- s'/s = -1............3) Real because s' = positive sign .....as M= -1 (equal size as the object, inverted)

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