1. A proton moves with a speed of 300 m/s in a direction 200 degrees countercloc
ID: 1271959 • Letter: 1
Question
1. A proton moves with a speed of 300 m/s in a direction 200 degrees counterclockwise of the +x axis through a magnetic field of 0.025 T directed in the +y direction. What is the magnitude and direction of the force exerted on the proton?
2. A 0.15 m wire carrying a current of 250 mA downward passes through a uniform magnetic field of 30 mT directed to the right. What is the magnitude and direction of the force exerted on the wire by the magnetic field?
3. A rectangular wire coil with 200 windings in the yz plane has dimensions 2cm x 6cm and carries a current of 3 A in the clockwise direction looking from the side of the +x axis. What is the magnitude and direction of the coil's magnetic moment?
4. A coil with magnetic moment of 0.05 A*m^2 directed 80 degrees counterclockwise of the +x axis in the xy plane is at a place where the magnetic field is 15 mT 30 degrees counterclockwise of the +x axis. What is the effect of the field on the coil? Give direction, magnitude and units.
I need answers to all 4 questions for points as well as all associated formulas! Thanks
Explanation / Answer
1. magnetic force F = qvB sin theta
F = 1.6e-19 * 300* 0.025 *sin 200
F = 4.107 *10^-10 N along +Z axis
-----------------------------------------------------------------
2. Magnetic force F = iLBsin theta
F = 0.250 * 0.15 * 0.030 * sin 90
F = 1.125 milli Newtons along out of the page
-------------------------------------------------
3. magnetic moment U = NiAsin theta
u = 200 * 0.02*0.06 * 3
u = 0.72 Tm^2
-------------------------------------------------------
4. magnetic fiedl creates torque on the coil
T = NiAB sin theta
T = 0.05 * 0.105 * sin (80-30)
T = 0.375 milli Nm along +z axis
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.