Electromagnetic waves of wavelength 0.170nm fall on a crystal surface. As the an

Question

Electromagnetic waves of wavelength 0.170nm fall on a crystal surface. As the angle of incidence is gradually increased, starting at 0?, you find that the first strong interference maximum occurs when the beam makes an angle of 23.4? with the surface of the crystal planes in the Bragg reflection.

Part A

What is the distance between the crystal planes?

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Part B

At what other angles will interference maxima occur?

Electromagnetic waves of wavelength 0.170nm fall on a crystal surface. As the angle of incidence is gradually increased, starting at 0?, you find that the first strong interference maximum occurs when the beam makes an angle of 23.4? with the surface of the crystal planes in the Bragg reflection.

Part A

What is the distance between the crystal planes?

d = nm

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Part B

At what other angles will interference maxima occur?

? = ?

Explanation / Answer

Part A)

Apply n(wavelength) = 2d(sinangle)

1(.170 X 10-9) = 2(d)(sin 23.4)

d = 2.14 X 10-10 m

Part B)

Additional angles are for increased n values.

When n = 2...

2(.170 X 10-9) = 2(2.14 X 10-10)(sin angle)

angle = 52.6o

When n = 3 or beyond, there are no more angles, because the sin value becomes larger than 1

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