The figure( Figure 1 ) shows a zero-resistance rod sliding to the right on two z

Question

The figure(Figure 1) shows a zero-resistance rod sliding to the right on two zero-resistance rails separated by the distance L = 0.488m . The rails are connected by a 12.7? resistor, and the entire system is in a uniform magnetic field with a magnitude of 0.662T .

Part A

Find the force that must be exerted on the rod to maintain a constant current of 0.138A in the resistor.

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Part B

What is the rate of energy dissipation in the resistor?

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Part C

What is the mechanical power delivered to the rod?

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Figure 1 of 1

Explanation / Answer

F = B*I*L

F = 0.622*0.138*0.488

F = 0.04189 N

2) P(dissipation ) = I^2 *R

P(dissipation) = (0.138^2)*12.7

P(dissipation) =0.242 W

3) P(mech) = P(dissipated) = 0.242 W

another method to calculate P (mech ) = F*v ,

so we need to find v,

we'll equate potential accross,

I*R = B*l*v, using this

P(mech) = F*v = B*i*l* v = I^2 * R = P(disspated)

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