1) Before beginning a long trip on a hot day, a driver inflates an automobile ti

Question

1) Before beginning a long trip on a hot day, a driver inflates an automobile tire to a gauge pressure of 1.9 atm at 293 K. At the end of the trip, the gauge pressure in the tire has increased to 2.3 atm.

Assuming the volume of the air inside the tire has remained constant, what is its tem- perature at the end of the trip?

Answer in units of K

2) Air is released from the tire during a short time interval, so that the temperature remains at the value found in part 1. Assume that the amount of air released is small enough for the tire

Explanation / Answer

(1) P1/T1 = P2/T2

2.9/293 = 3.3/T2

T2 = 333.412 K

(2)

now rearrange as p/n = RT/V, since only p and n change.
Initially, p/n = 3.3atm/n?
Finally, p/n = 2.9atm/n?
Since these initial states both = RT/V,
n?/ n?= 2.9/3.3 = 0.88, so 12%

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