A point charge q 1 = -3 ?C is located at the origin of a co-ordinate system. Ano

Question

A point charge q1 = -3 ?C is located at the origin of a co-ordinate system. Another point charge q2 = 7.8 ?C is located along the x-axis at a distance x2 = 7.4 cm from q1.

What is F12,x, the value of the x-component of the force that q1 exerts on q2?

Charge q2 is now displaced a distance y2 = 2.3 cm in the positive y-direction. What is the new value for the x-component of the force that q1 exerts on q2?

A third point charge q3 is now positioned halfway between q1 and q2. The net force on q2 now has a magnitude of F2,net= 11.69 N and points away from q1 and q3. What is the value (sign and magnitude) of the charge q3?

How would you change q1 (keeping q2 and q3 fixed) in order to make the net force on q2 equal to zero?

How would you change q3 (keeping q1 and q2 fixed) in order to make the net force on q2 equal to zero?

Explanation / Answer

1) F12= k*q1*q2/ r^2

2) F=k*q1*q2 / (((x2)^2 + 2.3^2)*(10^-4))

theta= arctan (2.3 / 7.4)

x component= Fcos (theta)

3) F = (force you found in #2) + 11.69

q3= (F*(1/4)(7.4^2+2.3^2)*(10^-4)) / (k*q2)

4) by increasing the magnitude

5) make it negative and increase the magnitude

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