A cord is wrapped around the rim of a solid uniform wheel 0.230m in radius and o

Question

A cord is wrapped around the rim of a solid uniform wheel 0.230m in radius and of mass 9.60kg . A steady horizontal pull of 48.0N to the right is exerted on the cord, pulling it off tangentially from the wheel. The wheel is mounted on frictionless bearings on a horizontal axle through its center.

Compute the angular acceleration of the wheel.

Compute the acceleration of the part of the cord that has already been pulled off the wheel.

Find the magnitude of the force that the axle exerts on the wheel.

Find the direction of the force that the axle exerts on the wheel. ( ?= degrees below the horizontal, away from the direction of the pull on the cord)

Explanation / Answer

I=m*r^2/2
A.
??=I*?

48*r=9.6*r^2*?/2
?=96/(9.6*0.230)
43.478 rad/s^2

B. 43.478*0.230
10m/s^2

C. sqrt(48^2+9.6^*9.81^2)
105.70 N

D) atan(9.6*9.81/96) below horizontal
44.45 degrees below horizontal

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