9.0/3 points | Previous Answers YF12 8.P.008.My Notes Question Part Points Submi

Question

9.0/3 points | Previous Answers YF12 8.P.008.My Notes Question Part Points Submissions Used Force of a Baseball Swing. A baseball has mass 0.145 kg. (a) If the velocity of a pitched ball has a magnitude of 50.0 m/s and the batted ball's velocity is 61.0 m/s in the opposite direction, find the magnitude of the change in momentum of the ball and of the impulse applied to it by the bat. kg·m/s (change in momentum) kg·m/s (impulse) (b) If the ball remains in contact with the bat for 2.00 ms, find the magnitude of the average force applied by the bat. N

Explanation / Answer

mass m=0.145 kg
consider ,initailly the ball is moving towards left
so
V1 = -50 m/s
after im pact
V2 = 61 m/s
a)
change in mometum = m(V2-V1) =0.145(61-(-50))=0.145(111) =16.095 kg-m/s

impulse on the ball by the bat =m(V2) =0.145(61) =8.845 kg-m/s

b)
from the relation
F*t = m(V2-V1)
F*2x10^-3 = 8.845
F = =4422.5 N
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