9. o1 points 1 Previous Answers OsColPhys2016 2.5.P027 My Notes Ask Your Te In a

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9. o1 points 1 Previous Answers OsColPhys2016 2.5.P027 My Notes Ask Your Te In a slap shot a hockey player accelerates the puck from a velocity of 8.00 m/s to 50.0 m/s in the same direction. If this takes 3.33 × 10-2 s, calculate the distance over which the acceleration acts. 1.11 x m Additional Materials Reading 10. 0/2 points | Previous Answers OSColPhys 2016 2.5.P028. My Notes Ask Your Teac A powerful motorcycle can accelerate from rest to 24.8 m/s (55 mi/h) in only 3.90 s (a) What is its average acceleration in m/s? 6.10 X m/s2 (b) How far does it travel in that time? 46.39 Additional Materials Reading

Explanation / Answer

a = (Vf-Vo)/t = (50-8)/3.32*10^-2 =1265.06 m/s^2.

d = Vo*t + 0.5a*t^2 = 0.95 m

2)

a = 24.8/3.90 = 6.35 m/s^2

d = 0.5 *at^2

d = 48.25m

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