A jet plane is flying at a constant altitude. At time t 1=0 it has components of

Question

A jet plane is flying at a constant altitude. At time t1=0 it has components of velocity vx= 86m/s , vy= 110m/s . At time t2= 33.5s the components are vx= 171m/s , vy= 37m/s .

PART A:) For this time interval calculate the average acceleration.

Give your answer as a pair of components separated by a comma. For example, if you think the x component is 3 and the y component is 4, then you should enter 3,4. Express your answer using two significant figures.

PART B:) Find the magnitude of the average acceleration.

Express your answer using two significant figures.

PART C.) Find the direction of the average acceleration (let the direction be the angle that the vector makes with the +x-axis, measured counterclockwise).

Explanation / Answer

cceleration is the change in velocity with time. When you have X and Y components, they are independent of each other since they are perpendicular. So changes in X have no effect on Y which means that we can consider the X component and the Y independently of each other.

change in time = 33.5s

change in X speed = 171 - 86 = 85 m/s
change in Y speed = 37 - 111 = -73 m/s

Ax = X acceleration = 85/33.5 = = 2.537 m/s^2
Ay = Y acceleration = -73/33.5 = -2.179 m/s^2

Magnitude of A = SQRT[Ax^2 + Ay^2)
Magnitude of A = SQRT(2.537^2 + 2.179^2)
Magnitude of A = 3.3443 m/s^2

X acceleration is positive and Y acceleration is negative so the vector acceleration will point at an angle beneath the X-axis.

tan(Angle) = Ay/Ax = -2.179/2.537 = -0.8588
Angle = -0.8588 radians = -40.66 degrees

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.