(20 POINTS) Two astronauts (let?s say George and Sandra) are drifting somewhat t
ID: 1263864 • Letter: #
Question
(20 POINTS) Two astronauts (let?s say George and Sandra) are drifting somewhat towards one another while in deep space, as shown. Specifically, George is moving with speed VG, and Sandra is moving with speed V5 = 8vG/S. When George and Sandra collide with one another, they hang on tight and move off in the same direction with speed vf = vG/2. George has mass mG = 1.60 ms where ms is Sandra?s mass. (a) (5PTS) What are the magnitude pG of George?s momentum, ps the magnitude of Sandra?s momentum, and P the magnitude of their combined final momentum. Express your answers in terms of mS and vG. (b) (5PTS) Chose a coordinate system for this problem, and draw arrows representing the vectors pG, pS, and pf. Be sure to include angles to represent the momentum directions. Define any and ail symbols that you introduce. (Hint: A clever choice of coordinate system here will simplify the rest of this problem a great deal.) (c) (5PTS) Using the diagram that you drew for part (b), determine the angle Theta0 at which the two astronauts collided. (d) (5PTS) Clearly this collision is completely inelastic because the two astronauts stick together, but just how inelastic is the collision? In other words, by what percent has their kinetic energy decreased?Explanation / Answer
Its given that,
Velocity of george = Vg
Mass = 1.6 Ms
that of sandra = Vs = 8Vg/5
Mass = Ms
Their speed after collision = Vf = Vg/2
(a)Magnitude of George's momentum = Pg = Mass of Georgre x his velocity
Pg = Vg x 1.6 Ms = 1.6MsVg
Ps = 8/5Vg x Ms = 1.6 MsVg
Pf = (1.6Ms + Ms) Vf = (2.6Ms)Vg/2
(d) KEg = 1/2(1.6Ms)Vg2 = 1.28MsVg2
KEs = 1/2 Ms (1.6Vg)2 = 0.8 MsVg2
KEf= 1/2 x (2.6Ms) (Vg/2)2 = 0.325MsVg2
There is a change of 40.63% in KE of Sandra and 25.39% KE of George.
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