a) What is the spacing,d, between slits of the gratings? b) The diffraction grat

Question

a) What is the spacing,d, between slits of the gratings?

b) The diffraction grating is replaced by a single slit of width a=0.50 mm. What is the width, in mm, of the central maximum on a screen 1.8m behind the screen?

c) how do you increse the points a question is worth? They changed it and now you can't increse the points.

a helium-neon based laser ( lambada = 633nm) illuminates a diffraction grating. The distance between the two m=1 bright fringes is 36 cm on a screen 2.3m behind the grating. a) What is the spacing,d, between slits of the gratings? b) The diffraction grating is replaced by a single slit of width a=0.50 mm. What is the width, in mm, of the central maximum on a screen 1.8m behind the screen? c) how do you increse the points a question is worth? They changed it and now you can't increse the points.

Explanation / Answer

(a) for diffraction grating

                              --------------------------1

lambda =wavelength of light,   tan@ = x/ D      (x= spacing of bright fringes= 36 *10-2 m)

tan@= 36*10-2 / 2.3                                         ( D = Distance between the screens)

@ = 8.890

d= m* lambda / sin@                         (from equation 1)

=1* 633*10-9 / sin 8.89

d= 4.09* 10-6 m

(b) width of central maxima = 2*D*wavelength of light / a                        (a= width of slit)

= 2* 2.3* 633*10-9 / 0.50*10-3

= 5.8 mm

(c) In this experiment we can use white light instead of monochromatic light to get coloured band .

band width is directly proportional to wavelength. red light has higher wavelength will have wider band.

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