A point charge q is placed near a second different charge Q; Charge q exerts a f
ID: 1262581 • Letter: A
Question
A point charge q is placed near a second different charge Q; Charge q exerts a force F on Q.
For the following independent scenarios, compute the ratio of the new force that q will exert on Q to the
original force F. Rank these ratios from smallest to largest. Explain your reasoning clearly please. Thanks.
a) Double the charge Q to 2Q.
b) Double the distance between the charges.
c) Cut the distance between charges in half
d) Cut the charge of Q in half, and cut the distance between charges in half
Explanation / Answer
original F = kqQ/r2
rank
Fb < F< Fa = Fd < Fc
a) Double the charge Q to 2Q. Fa = 2kqQ/r2
b) Double the distance between the charges. kqQ/4r2
c) Cut the distance between charges in half 4kqQ/r2
d) Cut the charge of Q in half, and cut the distance between charges in half 2kqQ/r2
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