A magnetic field exerts a torque on each of the current carrying single loops of

Question

A magnetic field exerts a torque on each of the current carrying single loops of wire shown in the figure below. The loops lie in the xy-plane, each carrying the same magnitude current, and the uniform magnetic field points in the positive x-direction. Rank the coils by the magnitude of the torque exerted on them by the field, from largest to smallest.

A magnetic field exerts a torque on each of the current carrying single loops of wire shown in the figure below. The loops lie in the xy-plane, each carrying the same magnitude current, and the uniform magnetic field points in the positive x-direction. Rank the coils by the magnitude of the torque exerted on them by the field, from largest to smallest.

Explanation / Answer

The torque acting on a loop placed in uniform magnitude is given by the formula

? = BiA

Here B and i is same for all so the torque is heigh for which have the heigher

area.

Area of A = 1 * 2 = 2 m^2

Area of B = ?r^2 = 3.14 * 0.5^2 = 0.785 m^2

Area of C = (1/2)bh = 0.5 * 1 * 3 = 1.5 m^2

Area of A is more than B and C.

Since the area of A is more than B and C, the torque acting on it is more

The torque on A > Torque on C >Torque on B

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