Your friend is catching a falling basketball after it has passed through the bas

Question

Your friend is catching a falling basketball after it has passed through the basket. Her hands move straight down while catching the ball. Take that it takes about 0.10 s for the player to lower her hands to stop the ball. Assume the mass of the ball is 0.60 kg, and that it has fallen a vertical distance of 1.2m before reaching the players hand. Determine the average force that her hands exert on the ball while catching it.

I have tried the answer, 29 N, 72N and 2.9 N and all of them were wrong, please help!!!

Thank you so much!

Explanation / Answer

Note that the velocity upon catching is

v = sqrt(2gh) = 4.850 m/s

As

a = delta v/delta t

Then, as delta t = 0.10 s

a = 48.5 m/s^2

As

F - mg = ma

---> F = mg + ma

=35.0 N [ANSWER]

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