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1. A 1 kg block of wood is moving with a velocity of 10 m s^-1 on top of a table

ID: 1259921 • Letter: 1

Question

1. A 1 kg block of wood is moving with a velocity of 10 m s^-1 on top of a table. The coefficient of kinetic friction between the block of wood and the table is 0.1. The block of wood is a cube with sides of 12 cm. a) How far does the block move before coming to a stop? b) If momentum id conserved, where did the momentum of the block go? c) The block slows down because of the frictional force between the block and the block. However, if the frictional force acts at the bottom of the block and the blocks center of mass is in the center of the block then there must be a torque acting on the block. Calculate this torque. Why doesn?t this torque cause the block to rotate?

Explanation / Answer

a) acceleration due to friction

a = ug

u = 0.1

g =9.8 m/s2

a = -0.98m/s2

Vo = 10m/s

V =0

we have

x = (V2- Vo2)/2a

that gives distance covered x = 51m

b) the momentum is not conserved as there is an external force in the form of friction is acting on the body.

c) the net torque acting on the block is zero as the torque due to friction is balalnced by the torque due to the weight