1. 8 Part A A cart of mass 1.05 kg traveling 1.42 m/s inelastically strikes a st

Question

1. 8

Part A

A cart of mass 1.05 kg traveling 1.42 m/s inelastically strikes a stationary mass of 1.79 kg. What is the total momentum of the system after the collision?

Please remember proper units and significant figures.

Part B

A cart of mass 1.82 kg traveling 3.11 m/s completely inelastically strikes a stationary mass of 0.34 kg. What is the final velocity of the system after the collision?

Please remember proper units and significant figures

Please provide steps on how to find the answer. The clear/neat and correct answer I will give a full rate.

Explanation / Answer

Part A)

by linear momentum conservation

m1u1 +m2u2=(m1+m2)v

total momentum of the system after the collision =m1u1 +m2u2=1.05*1.42=1.49 kgm/s

Part B)

by linear momentum conservation

m1u1 +m2u2=(m1+m2)v

1.82*3.11 =(1.82+0.34)v

v =2.62m/s

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