A proton traveling at 3.90km/s suddenly enters a uniform magnetic field of 0.800
ID: 1259594 • Letter: A
Question
A proton traveling at 3.90km/s suddenly enters a uniform magnetic field of 0.800T , traveling at an angle of 55.0o with the field lines (see the figure (Figure 1) ). Note that both the Magnetic Field and the velocity of the proton are in the plane of the page.
Part A
Find the direction of the force this magnetic field exerts on the proton.
Please ChooseThe force is directed into the page. The force is directed out of the page.
Part B
Find the magnitude of the force this magnetic field exerts on the proton.
Part C
If you can vary the direction of the proton's velocity, find the magnitude of the maximum and minimum forces you could achieve.
Answer the question in the order indicated. Separate your answers using comma.
Part D
How the velocity should be oriented to achieve the forces in part (C).
How the velocity should be oriented to achieve the forces in part (C).
Part E
What would the answers to part (A) be if the proton were replaced by an electron traveling in the same way as the proton?
Please ChooseThe force is directed into the page. The force is directed out of the page.
Part F
What would the answers to part (B) be if the proton were replaced by an electron traveling in the same way as the proton?
F = N A proton traveling at 3.90km/s suddenly enters a uniform magnetic field of 0.800T , traveling at an angle of 55.0o with the field lines (see the figure (Figure 1) ). Note that both the Magnetic Field and the velocity of the proton are in the plane of the page. Part A Find the direction of the force this magnetic field exerts on the proton. Please ChooseThe force is directed into the page. The force is directed out of the page. Part B Find the magnitude of the force this magnetic field exerts on the proton. F = N Part C If you can vary the direction of the proton's velocity, find the magnitude of the maximum and minimum forces you could achieve. Answer the question in the order indicated. Separate your answers using comma. Fmax,Fmin = N Part D How the velocity should be oriented to achieve the forces in part (C). How the velocity should be oriented to achieve the forces in part (C). F is maximum when v? is perpendicular to B? . F is minimum when v? is perpendicular to F? . F is maximum when v? is perpendicular to B? . F is minimum when v? is either parallel or antiparallel toB? . F is maximum when v? is parallel to B? . F is minimum when v? is perpendicular to B? . Part E What would the answers to part (A) be if the proton were replaced by an electron traveling in the same way as the proton? Please ChooseThe force is directed into the page. The force is directed out of the page. Part F What would the answers to part (B) be if the proton were replaced by an electron traveling in the same way as the proton? F? = NExplanation / Answer
Part A- The force is directed into the page (Using Fleming Right Hand Rule).
PartB- Force F=qvBsintheta=4.08*10-16N
PartC force will be maximum if sintheta=1 and will be minimum if sintheta=-1 (here theta is the angle between v&B)
hence Fmax=4.992*10-16 and Fmin= -4.992*10-16
Part E- The force is directed out of the page. it is just opposite of proton.
Part F- magnitude will be same but direction will be change.
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