The two wires shown in the figure carry currents of I = 5.14 A in opposite direc

Question

The two wires shown in the figure carry currents of I = 5.14 A in opposite directions and are separated by a distance of d0 = 9.43 cm. Calculate the net magnetic field at a point midway between the wires. Use the direction out of the page as the positive direction and into the page as the negative direction in your answer.Calculate the net magnetic field at point P1- that is 8.37 cm to the right of the wire on the right.Calculate the net magnetic field at point P2- that is 20.7 cm to the left of the wire on the left.

The two wires shown in the figure carry currents of I = 5.14 A in opposite directions and are separated by a distance of d0 = 9.43 cm. Calculate the net magnetic field at a point midway between the wires. Use the direction out of the page as the positive direction and into the page as the negative direction in your answer.Calculate the net magnetic field at point P1 - that is 8.37 cm to the right of the wire on the right.Calculate the net magnetic field at point P2 - that is 20.7 cm to the left of the wire on the left.

Explanation / Answer

B = u0*I / 2pi*d  

here u0 = 4pi x 10-7

I = 5.14 A

due left wire magnetic field is upwards and due right one B is donwards.

at mid point :

Bnet = u0*I / 2pi [ 1 / (0.0943/2)   - (1 / (0.0943) ]   = 0

at P1 :

Bnet = u0 * I / 2 pi [ (1 / (0.0943 + 0.0837) ) - ( 1 / (0.0837)) ]

     =   - 6.51 x 10-6 T

at P2 :

Bnet = u0 * I / 2 pi [ (1 / 0.207 ) - ( 1 / (0.207 +0.0943)) ]
           = 1.55 x 10-6 T

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.