H0 : ?d ? 0 H1 : ?d > 0 The following sample information shows the number of def

Question

H0 : ?d ? 0 H1 : ?d > 0 The following sample information shows the number of defective units produced on the day shift and the afternoon shift for a sample of four days last month. Day 1 2 3 4 Day shift 12 12 16 19 Afternoon shift 10 10 12 15 At the .05 significance level, can we conclude there are more defects produced on the afternoon shift? Hint: For the calculations, assume the Day shift as the first sample. (a) State the decision rule. (Round your answer to 2 decimal places.) Reject H0 if t >

Explanation / Answer

d=14.75-11.75=3

d/n=.89

t=3/.89=3.37

t(.05,8)=1.39

Reject H0 if t >1.39

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