Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Question 7 Galvanized Products is considering purchasing a new computer system f

ID: 1161659 • Letter: Q

Question

Question 7 Galvanized Products is considering purchasing a new computer system for their enterprise data management system. The vendor has quoted a purchase price of $90,000. Galvanized Products is planning to borrow 1/4th of the purchase price from a bank at 15.00 % compounded annually, me loan is to be repaid using equal annual payments over a 3-year period. The computer system is expected to last 5 years and has a salvage value of $4,400 at that time. Over the 5-year period, Galvanized Products expects to pay a technician $27,000 per year to maintain the system but will save $60,000 per year through increased efficiencies. Galvanized Products uses a MARR of 18.00 %/year to evaluate investments. a. What is the present worth of this investment? Do all calculations to 5 decimal places and round final answer to 2 decimal places. Tolerance is /-1.00. b. What is the decision rule for judging the attractiveness of investments based on present worth? Should the new computer system be purchased? Click here to access the TVM Factor Table Calculator

Explanation / Answer

a)

Purchase price of computer system = $90,000

Amount to be borrowed = $90,000 * ¼ = $22,500

Interest rate (r)= 12%

Term of loan (n)= 3 years

Annual loan payment = (Loan amount *r)/{1-(1+r)-n}

Annual loan payment = ($22,500*0.12)/(1-1.12-3) = $2,700/0.2882 = $9,368

The interest payment and principal portion in the loan repayment can be found by preparing a loan amortisation schedule as below:

Year

Beginning loan balance

Interest @ 12%

Loan payment

Principal

Ending loan balance

1

$ 22,500

$ 2,700

$ 9,368

$ 6,668

$ 15,832

2

$ 15,832

$ 1,900

$ 9,368

$ 7,468

$ 8,364

3

$ 8,364

$ 1,004

$ 9,368

$ 8,364

$ 0

The annual cash flows from the project can be calculated a below:

Year

0

1

2

3

4

5

Savings due to increased efficiency

$ 59,000

$ 59,000

$ 59,000

$ 59,000

$ 59,000

Technician charges

-$ 30,000

-$ 30,000

-$ 30,000

-$ 30,000

-$ 30,000

Interest payment

-$ 2,700

-$ 1,900

-$ 1,004

Net cash flow from operations

$ 26,300

$ 27,100

$ 27,996

$ 29,000

$ 29,000

Cash paid for computer system

-$ 67,500

Loan repayment

-$ 6,668

-$ 7,468

-$ 8,364

Salvage value

$ 5,000

Non operating cash flows

-$ 67,500

-$ 6,668

-$ 7,468

-$ 8,364

$ 0

$ 5,000

Net cash Inflow/(outflow)

-$ 67,500

$ 19,632

$ 19,632

$ 19,632

$ 29,000

$ 34,000

Present value at 20%

1

0.8333

0.6944

0.5787

0.4823

0.4019

Present value of cash flows

-$ 67,500.00

$ 16,359.35

$ 13,632.46

$ 11,361.04

$ 13,986.70

$ 13,664.60

$ 1,504.15

Present worth of this investment = $1,504.15

b)

If the present worth of project is positive, then the project is acceptable.

c)

Yes, new computer system should be purchased because the present worth is positive.

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote