arch the web S Economics 0800 Secticn 1 3 Pre-Test04 ] Schoology P Pearson Sign

Question

arch the web S Economics 0800 Secticn 1 3 Pre-Test04 ] Schoology P Pearson Sign In 2 https:/htuskegee schoo?ogy.com/assignment/ GY a Home Courses GroupsResources 144262303 7 /assessment Section 1 Question 1 of 10 1 Page 1 of 10 Question 1 (2 points) If tubing averages 30 defects per 100 meters, what is the probability of finding more than three defects in a randomly chosen 10-meter piece of tubing? O 0.1992 O b 0.3528 ?? 0.2240 O d 0.1680 Next Page nce you click Next Page Time left for this 57:31 8 6 8 9

Explanation / Answer

Solution: 0.1992

Working:

lamda = 30/10 = 1.3

e^-lamda x (lamda^r/r!)

e^-1.3 * (1.3^2/2!) = 0.1992

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