Section3 lonic Bonds Example Sodium (Na) has l l procons and i i electrons (atom

Question

Section3 lonic Bonds Example Sodium (Na) has l l procons and i i electrons (atomic #-11 ), Chlorine (ci) has 17 protons and 17 electrons (atomic # =17). Because of this. Na has a single electron in its 3-d energy level and CI has seven. To bond ionically: CI takes this single electron from Na, completes its 3'h energy level, and stabilizes both atoms. As a result, Na has fewer electrons than protons (now, 10 electrons) and CI has more electrons than protons (now, 18 electrons). Therefore, Na has a Ci 17 protons, 11 protons 0o 35.453 onic Bonding 00- 00. 888 88 Na' I1 protons, 10 electrons CI 17 protons, 18 electrons Question 1: Look up Sodium (Na) and Fluorine (F) on the periodic table of elements. How many protons does an atom of Na have? How many electrons does an atom of Na have? How many electrons are in the 3d energy level of Na? How many electrons are in the 2nd energy level of F?-- After bonding, will Na be positively charged (cation) or negatively charged (anion)?

Explanation / Answer

Number of protons for Na is 11

Number of electrons for Na is 11

Number of electrons in the third energy level of Na is 8

Number of electrons in the second energy level of F is 7

Sodium has 11 electrons that orbit the nucleus. The first two shells within sodium are full and only one electron occupies the third shell. Therefore, it is easier for sodium to lose an electron and become positive

Related Questions

Navigate

• Browse (All)
• Browse S
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.