a. Compare Means of Three of More Groups Descriptives X24 -- Likely to Recommend

Question

a.   Compare Means of Three of More Groups

Descriptives

X24 -- Likely to Recommend

N

Mean

Std. Deviation

Std. Error

95% Confidence Interval for Mean

Minimum

Maximum

Lower Bound

Upper Bound

No Children at Home

159

4.86

1.581

.125

4.61

5.11

1

7

1-2 Children at Home

101

4.68

1.449

.144

4.40

4.97

1

7

More Than 2 Children at Home

89

5.09

1.520

.161

4.77

5.41

1

7

Total

349

4.87

1.531

.082

4.71

5.03

1

7

ANOVA

X24 -- Likely to Recommend

Sum of Squares

df

Mean Square

F

Sig.

Between Groups

7.839

2

3.919

1.678

.188

Within Groups

808.098

346

2.336

Total

815.937

348

Multiple Comparisons

Dependent Variable:   X24 -- Likely to Recommend

Scheffe

(I) X33 -- Number of Children at Home

(J) X33 -- Number of Children at Home

Mean Difference (I-J)

Std. Error

Sig.

95% Confidence Interval

Lower Bound

Upper Bound

No Children at Home

1-2 Children at Home

.178

.194

.657

-.30

.66

More Than 2 Children at Home

-.228

.202

.530

-.73

.27

1-2 Children at Home

No Children at Home

-.178

.194

.657

-.66

.30

More Than 2 Children at Home

-.407

.222

.189

-.95

.14

More Than 2 Children at Home

No Children at Home

.228

.202

.530

-.27

.73

1-2 Children at Home

.407

.222

.189

-.14

.95

2. Compare and contrast the means of three or more groups. Are households with more children more likely OR less likely to recommend their favorite Mexican restaurant than are households with fewer children? Explain fully your conclusion. Don't guess. Support your answer by providing the mean that was computed.    

Descriptives

X24 -- Likely to Recommend

N

Mean

Std. Deviation

Std. Error

95% Confidence Interval for Mean

Minimum

Maximum

Lower Bound

Upper Bound

No Children at Home

159

4.86

1.581

.125

4.61

5.11

1

7

1-2 Children at Home

101

4.68

1.449

.144

4.40

4.97

1

7

More Than 2 Children at Home

89

5.09

1.520

.161

4.77

5.41

1

7

Total

349

4.87

1.531

.082

4.71

5.03

1

7

Explanation / Answer

Before starting with the comparision of means of the three or more groups groups we need to first check if the model is significant or not?

For that we use ANOVA table and in that we check the F- test. Keeping significance level as .05 and p- value is .188 (given) we say overall the model is not significant.

But this does not conclude that there cant be relation between two means...So we compare and contrast the means of different groups.

It is as follows:-

1) No children at home and 1-2 children at home. We see the mean difference to be .178. But to make sense from this mean we need to see that p- value of this group. p value which is .657 (given) is more than .05 therefore we say that we accept the null hypothesis and household with more children are not more likely OR less likely to recommend their favorite Mexican restaurant than are households with fewer children.

2) No children at home and more than two children at home.  We see the mean difference to be -.228. But to make sense from this mean we need to see that p- value of this group. p value which is .53 (given) is more than .05 therefore we say that we accept the null hypothesis and household with more children are not more likely OR less likely to recommend their favorite Mexican restaurant than are households with fewer children.

3) 1-2 children at home and more than two children at home. We see the mean difference to be -.407. But to make sense from this mean we need to see that p- value of this group. p value which is .189 (given) is more than .05 therefore we say that we accept the null hypothesis and household with more children are not more likely OR less likely to recommend their favorite Mexican restaurant than are households with fewer children.

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.