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1. For each of the following processes, deduce whether the quantities q, w, AU,

ID: 1089592 • Letter: 1

Question

1. For each of the following processes, deduce whether the quantities q, w, AU, AH, AS, and AS(total) are positive, zero, or negative. MAKE A TABLE: you can label the processes in the first column by the letters a) through g). No explanations are requested, but you will learn A LOT by thinking these through. a) reversible melting of ice at 1 atm and 0 °C. b) reversible boiling of water at 1 atm and 100 °C. c) reversible adiabatic expansion of an ideal gas d) reversible isothermal compression of an ideal gas e) reversible heating of an ideal gas at constant P f) adiabatic expansion of an ideal gas into vacuum (not reversible) g) adiabatic expansion of a gas with only attractive forces into vacuum (not reversible)

Explanation / Answer

a)

q -->positive, heat is added

w --> almost zero, no change in volume (considereably)

dU = --> increases since liquid > solid in intermolecular forces

dH = --> increases since liquid > solid in intermolecular forces

dSsystem --> increases since liquid has more chaos than solid

dStotal --> since reversible = 0

b)

q -->positive, heat is added

w --> positive since the change in volume is veyr high considereably

dU = --> increases since gas > liquid in intermolecular forces

dH = -->  increases since gas > liquid in intermolecular forces

dSsystem --> increases since gas has more chaos than liquid

dStotal --> since reversible = 0

c)

q -->negative, heat is lost

w --> positive since the change in volume, and it expands

dU = --> decrease since expansion implies decrease in T

dH = -->  decrease since expansion implies decrease in T

dSsystem --> increases since more chaos

dStotal --> since reversible = 0

d)

q --> Heat is lost by system

w --> Work must be negtive, since changes in volume

dU = --> 0, since no change in T

dH = -->  0, since no change in T

dSsystem --> Decreases, since it is acompression, the system gest ordered

dStotal --> since reversible = 0