Eq 2: Dper = a-c=a(ae) Dper = a(1-e) Equation 3: Dap=a+c=a+(ae) Dap = a(1+e) Equ

Question

Eq 2: Dper = a-c=a(ae)

Dper = a(1-e)

Equation 3: Dap=a+c=a+(ae)

Dap = a(1+e)

Equation 4: vper/vap = Dap / Dperi

2. Using the information in Table 1 and Equations 2 and 3 on p. 6-2, calculate showing all your work perihelion than it i at aphelion. What month is it(in the northern r the Earth is at perihelion than it is at aphelion . What month is it (in the nort hemisphere) when the Earth is at perihelion (go find this on the Internet)? Are you surprised by either of these pieces of information? Explain why or why not. Mercury travels 39 km/sec when it is at its farthest from the Sun. Using the information in Table 1, Equations 2 and 3 on p. 6-2, and Equation 4 on p. 6-9, calculate how fast Mercury travels when it is at its closest to the Sun. Show all your work. 3.

Explanation / Answer

Answer:2

Earth's perihelion distance can be calculated by the given following equation:

Dper= a(1-e)

Dper= 1 (1 - 0.017)

Dper=  0.983

And the Earth's aphelion distance can be calculated by the given following equation:

Dap = a(1+e)

Dap = 1(1+0.017)

Dap = 1.017

And the difference between them are 1.017 - 0.983= 0.034

And the earth is at perihelion in the month of January.

These outcomes signifies the role of rotation as well as tilt of earth towards sun according to which distance varies.

Answer:3

The velocity of mercury when it is at closest to the sun.

Vper / Vap = Dap / Dperi

Vper= Dap / Dperi * Vap

Dap= a(1+e)= 0.3871* ( 1+ 0.206)

Dap= 0.3871 ( 1.206)= 0.4668426

Dperi = a(1-e)= 0.3871* (1- 0.206)

Dperi = 0.3871 *0.794

Dperi = 0.3073574

Now, put these values in the following equation:

Vper= Dap / Dperi * Vap

Vper= 0.4668426 / 0.3073574 * (39)

Vper= 59.23 km /second

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