KEPLER\'S LAWS 2. The third law (Eq. 1) from page 6-1, can be confirmed by the p

Question

KEPLER'S LAWS 2. The third law (Eq. 1) from page 6-1, can be confirmed by the planetary data in Table 1. For all the objects, first square the period "P", then cube the semimajor axes "a". List the results in the proper column. Compare your results. Do your values confirm Kepler's Third Law? If there are any significant differences between the values in column 5 (P2) and those in column 3. 6 (a), what is a possible reason for this? In this lab, we will again be using the computer. Follow your instructor's directions for accessing the Kepler program. This program will allow you to plot ellipses by entering the semimajor axis and the hichever planet you wish into the appropriate eccentricity. To do this, type the values associated with w nd click the Suhmit button, Be careful what you enter. The values need a decimal. Note: the surn

Explanation / Answer

2) According to the third law of the kepler's planetory movement it is stated that the square of the orbital period of a planet is such that it directly proportional to the cube of the semi major axis of its axis. this law stand to demonstrate the relationship between distance of the planet from the center of sun and their orbital periods.

From the given table if suppose we are going to square the P and cube the a then we can find the following comparison of data from the given table.

mercury-

p^2= .05800 a^3= .05800

venus-

p^2= .37845 a^3= .37846

earth-

p^2= 1 a^3= 1

mars-

p^2= 3.53740 a^3= 3.53751

jupiter-

p^2= 140.73077 a^3= 140.73077

saturn-

p^2= 867.06691 a^3= 867.06691

uranus-

p^2= 7059.3603 a^3= 7059.83452

neptune-

p^2= 27159.02 a^3= 27189.44132

we can easily analyse and compare the law validity even if we dont do for dwarft planet or comet. because we analyses it on live planets and which is most important. so just focussed on these live planet from mercury to neptune we can see that the data are very much accurate and appropriate as well as close to the values listed in table. from this we conclude that law of kepler is valid and thus we can confirm it.

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3) Accordig to the heisenberg uncertainity principle, we can understand the fact of difference in the values listed for square of P and cube of A. for this concept we know that at a moment of time it is not possible to measure accurately the simulataneous relationship between velocity of body means planet here and exect position of planet at that moment of time. due to which some uncertainity as well as differences arises for P and A. hence it is valid to accept in this format.

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