Be sure to answer all parts. Butane gas is compressed and used as a liquid fuel

Question

Be sure to answer all parts. Butane gas is compressed and used as a liquid fuel in disposable cigarette lighters and lightweight camping stoves. Suppose a lighter contains 5.83 mL of butane (d= 0.579 g/mL). (a) How many grams of oxygen are needed to burn the butane completely? g O2 (b) How many moles of H2O form when all the butane burns? moles H20 (c) How many total molecules of gas form when the butane burns completely? x 10 (select)' molecules ofgas (Enter your answer in scientific notation.)

Explanation / Answer

mass of butane = density x volume

                         = 0.579 x 5.83

                        = 3.38 g

balanced equation :

2 C4H1O + 13 O2 -------------------------> 8CO2 + 10 H2O

116.24 g         416 g                                  352g        180 g

3.38 g

a)

mass of O2 = 416 x 3.38 / 116.24 = 12.1 g

mass of O2 = 12.1 g

b)

mass of H2O = 180 x 3.38 / 116.24 = 5.23 g

moles of H2O = 5.23 / 18.02 = 0.291

moles of H2O = 0.291

c)

8 mol CO2 --------------> 10 mol H2O

X mol CO2----------------> 0.291 mol H2O

moles of CO2 = 0.291 x 8 / 10 = 0.232

total gas moles = 0.232 + 0.291 = 0.523

molecules of gas = 0.523 x 6.023 x 10^23

                         = 3.15 x 10^23

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