Barium sulfate, BaSO4 , is used in medical imaging of the gastrointestinal tract

Question

Barium sulfate, BaSO4 , is used in medical imaging of the gastrointestinal tract because it is opaque to X rays. A barium sulfate solution, sometimes called a cocktail, is ingested by the patient, whose stomach and intestines can then be visualized via X-ray imaging. If a patient ingests 400 mL of a saturated barium sulfate solution, how much toxic Ba 2+ ion has the patient consumed? The solubility product K sp of BaS O 4 is 1.10× 10^ 10 .

There are some data that suggest that zinc lozenges can significantly shorten the duration of a cold. If the solubility of zinc acetate, Zn(CH3COO)2, is 43.0 g/L, what is the solubility product Ksp of this compound?

Express your answer numerically.

Explanation / Answer

1)

Answer

0.576mg

Explanation

Dissolution of BaSO4 is given by following equation

BaSO4(s) <- - - - - - - > Ba2+(aq) + SO42-(aq)

Ksp = [Ba2+][SO42-]= 1.10×10-10 M2

   [Ba2+][SO42-] = 1.10×10-10M2

[Ba2+] = [SO42-]

So,

x2 = 1.10×10-10M2

   x = 1.049×10-5M

Therefore,

[Ba2+] = 1.049×10-5 M = 1.049×10-5 mol/L

Volume of solution = 400ml

No of moles of Ba2+ = (0.00001049mol/1000ml)×400ml =0.000004196mol

molar mass of Barium = 137.327g/mol = 0.000576g = 0.576mg

2)

Answer

5.15×10-2

Explanation

Chemical equation for the dissolutiion of Zn(CH3COI-)2

Zn(CH3COO)2 (s) <- - - - - - - - > Zn2+(aq) + 2CH3COO-(aq)

Ksp = [Zn2+][CH3COO-]2

Solubility of Zn(CH3COO)2 =43.0g/L

molar mass of Zn(CH3COO)2 = 183.48g/mol

No of mole of Zn(CH3COOH) = 43.0g/183.48g/mol =0.23436mol

Molar solubility of Zn(CH3COO)2 = 0.23436mol/L

[Zn2+] = 0.23436M

[CH3COO-] = 2×0.23436M = 0.46872M

Ksp = 0.23436M × (0.46872M)2 = 5.15×10-2

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