Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

4Three colorless solutions in test tubes, with no labels, are in a test tube rac

ID: 1083435 • Letter: 4

Question

4Three colorless solutions in test tubes, with no labels, are in a test tube rack on the laboratory bench Lying beside the tests tubes are three labels: 0.10 M Na,CO, 0.10 M HCI, and 0.10 M KOH. You are to place the labels on tubes using only the three solutions present. Here are your tests: A few drops of the solution from test tube 1 added to a similar volume of the solution in test tube 2 produces no vis- ible reaction but the solution becomes warm. .A few drops of the solution from test tube 1 added to a similar volume of the solution in test tube 3 produces carbon dioxide gas. Identify the labels for test tubes 1, 2, and 3

Explanation / Answer

A:- Test tube 1 = 0.10 M HCl

     Test tube 2 = 0.10 M KOH

     Test tube 3 =0.10 M Na2CO3

=> When a few drops of solution from test 1 (0.10 M HCl) is added to the test tube 2 (0.10 M KOH), neutralization reaction is takes place and is a exothermic reaction. As a result the solution becomes warm.

HCl(aq)   + KOH(aq) -------> KCl(aq) + H2O(l) + heat

=> When a few drops of solution from test 1 (0.10 M HCl) is added to the test tube 3 (0.10 M Na2CO3), produces CO2 gas.

2 HCl(aq) + Na2CO3(aq)   ------>   2 NaCl(aq) +   H2O(l) + CO2(g)

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote