Print culator Periodic Table Question 14 of 22 University Science Books General

Question

Print culator Periodic Table Question 14 of 22 University Science Books General Chemistry 4th Edition presented by Sapling Leaming Suppose that you place exactly 100 bacteria into a flask containing nutrients for the bacterià and that you find the following data at 37 t (min) Number of bacteria 16.0 32.0 48.0 64.0 100 200 400 800 1600 What is the order of the rate of production of the bacteria? How many bacteria will be present after 128 min? Number O zero order O first order O second order bacteria What is the rate constant for the process? Number units Select answer O Prvous Gue up & View Solution Check Answer 0 Next Exit- Hint

Explanation / Answer

after every 16 sec number of bacteria get double
so, order of rate of production is 1
first order.

use,
ln([A]/[A0]) = k*t
use, first two date from table
ln(200/100) = k*16
ln2 = k*16
k*16 = 0.693
k = 0.0433 sec^-1

again use,
ln([A]/[A0]) = k*t
for t=0 and t=128
ln([A]/100) = 0.0433*128
ln([A]/100) = 5.54
[A]/100 = 254.7
[A] = 225470
it is nearly equal to 25600

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