Using a private space craft to visit the space station requires 99.7 trillion BT

Question

Using a private space craft to visit the space station requires 99.7 trillion BTU of energy
the best fuel for the mission will have the highest ratio of energy to volume
based on the fuel data presented in the table select The optimal fuel and calculate the total gallons of fuel required
So I got gasoline right as the optimal fuel, but part 2. “ how many gallons of fuel are required “ is where I went wrong the answer I have in the box is the wrong answer but he one I got so I’m confused on what to do for the second part :(
1 trillion equals 1×10 to the 12th power I thousand ML‘s equals one L 454 g equals 1 pound Ma Sapling Learning Using a private space craft to visit the space station requires 99.7 trillion BTU of energy. The best fuel for the mission will have the highest ratio of energy to volume. Based on the fuel data presented in the table, select the optimal fuel and calculate the total gallons of fuel required Fuel Energy Output Density (g/mL) 0.820 0.737 0.789 Hydrogen 61,100-0710 Kerosene 18,500 Gasoline 20,900 0 Ethanol 11,500 What is the optimal fuel? O Kerosene Gasoline O Ethanol O Hydrogen() How many gallons of fuel are required? Number 710076363 gallons Previous Give Up & View Solution ) Check AnswerNext Hint

Explanation / Answer

So considering that gasoline is the right option I am solving the second part:

First convert Energy output from Btu/ lb to Btu/ g
20900 Btu/ lb = (20900 Btu/ lb) x ( 1 lb/ 454 g)
= 46.03524229 Btu/ g
Now calculate the energy per ml = (46.03524229 Btu/ g) x (0.737 g/ mL)
   = 33.92797357 Btu/ mL
Now, calculate the mL of gasoline required to produce 99.7 trillion Btu energy:
   = (99.7 x 1012 Btu)/ (33.92797357 Btu/ mL)
= 2.938578097 x 1012 mL
Now we have to just convert mL to gallon
2.938578097 x 1012 mL = (2.938578097 x 1012 mL) x (1 Liter/ 1000 mL) x ( 1 Gallon/ 3.785 Liter)
   = 776374662.4 Gallons

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