Question 15 & 16!! Thank you! tient in the equation 2 Li (s) + 2 H20 (I) 2 LiOH
ID: 1075981 • Letter: Q
Question
Question 15 & 16!! Thank you!
tient in the equation 2 Li (s) + 2 H20 (I) 2 LiOH (aq) + H2 (g) Reduced Reducing agent: Oxidizing agent: balance, and include physical states for the aqueous reaction betwee hydrob lithium hydroxide. Rxn type? 11. Write, balance, and include physical states for the aqueous reaction between leadll) nitrate and calcium chloride. Rxn type? 12. Write, balance, and include physical states for the aqueous reaction between solid aluminum metal and 13. Draw what 2 formula units of each chemical would look like in water. (Hint: Uise solubilityrules) Hydrochloric acid lead(II) chloride barium hydroxide nitric acid solution? 14. How many moles are in 250.0 mL of a 0.15 M 15. What volume of base is required to reach the equivalence point in a titration of 25.00 ml of 0.20 M sulfuric acid with 0.35 M potassium hydroxide? Write the balanced chemical equation first. 16. How many grams of precipitate could I make if I started with 6.00 mL of 0.10 M silver nitrate and 5.00 mL of 0.15 M potassium chloride according to the equation: KNO3(aq) AgCl(s) + KCI(aq) AgNO3(aq) +Explanation / Answer
15)
Balanced chemical equation is:
H2SO4 + 2 KOH ---> K2SO4 + 2 H2O
Here:
M(H2SO4)=0.20 M
M(KOH)=0.35 M
V(H2SO4)=25.00 mL
According to balanced reaction:
2*number of mol of H2SO4 =1*number of mol of KOH
2*M(H2SO4)*V(H2SO4) =1*M(KOH)*V(KOH)
2*0.2 M *25.0 mL = 1*0.35M *V(KOH)
V(KOH) = 29 mL
Answer: 29 mL
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