Question 14 of 15 0.5 Points A Health and Fitness company would like to determin

Question

Question 14 of 15 0.5 Points A Health and Fitness company would like to determine if a new product improves cardiovascular fitness. A sample of 15 new customers agreed to take a treadmill test before and after using the product. The test measured how long they could run on the treadmill until they became exhausted or short of breath. The mean difference (after - before) for the customers was computed to be 2.3 minutes with a standard deviation of 5.4 minutes. Using a two-tailed test compute the test statistic and make the decision O A. Test Statistic: 1.65 O B. Test Statistic: 1.65 O c. Test Statistic: 2.04 0 D. Test Statistic: 204 Decision: Accept the null hypothesis Decision: Reject the null hypothesis Decision: Accept the null hypothesis Decision: Reject the null hypothesis

Explanation / Answer

test statistic

t= mean_diff/(sd_diff/sqrt(n))

mean_diff 2.3

sd_diff 5.4

n= 15

t= 1.65

p-value=

2*(1-P(T<|t|))

=T.DIST.2T(1.65,14)

0.121190172

answer:

a) t=1.65, accept the Null hypothesis

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