Triacylglyceride + H2O à Diacylgleride + R-COO+ H+ 1)As we will see in a later c
ID: 1075977 • Letter: T
Question
Triacylglyceride + H2O à Diacylgleride + R-COO+ H+
1)As we will see in a later chapter, the oxidation of NADH by oxygen NADH + H+ + 0.5O2 à NAD+ + H2O is a strongly favorable reaction in a cell that is respiring and this reaction is the basis for the energy we get from respiration. The overall E (reduction potential) for this reaction in the respiring cell must therefore be:
a) Positive
b) Negative
c) Zero
d) E could be positive or negative, but this tells us E0 must be positive
2) For a metabolic reaction that is proceeding in the forward direction (it is spontaneous under the conditions of the cell), the free energy change is always:
a) Positive
b) Negative
c) Zero
d) It can be positive or negative depending on the concentrations of the components in the cell
3) The pentose phosphate pathway involves a thermodynamically favorable redox reaction in which glucose + NADP à gluconic acid + NADPH. The overall redox potential (E) for this reaction under cellular conditions must be
a) Positive
b) Negative
c) Zero
d) It can be positive or negative depending on the concentrations of the components in the cell
4) Oxidizing an alcohol group (CH2OH) at the end of a carbon chain to a carboxylic acid (COOH) is
a) A one electron oxidation
b) A two electron oxidation
c) A three electron oxidation
d) A four electron oxidation
Explanation / Answer
1) Oxidation of NADH is taking place. that NADH is the reducing agent and oxygen is the oxidizing agent. Because the NAD couple has the more negative potential, the reaction is exergonic, G0 = (–).G=RTlnKeq=nFEcell so, Value of overall reduction potential E is positive. The right answer is option a.
2) As I discussed, the overall reaction is spontaneous then the free energy of reaction is negative(-). The right option is (b).
3) the net process of glycolysis involves the oxidation of glucose to pyruvate coupled to the reduction of NAD+ to NADH. Since the oxidation of glucose is more negative and the reduction of NAD+ is less negative than glucose it, this electron flow is thermodynamically favourable. The overall reduction potential E for a reaction is positive then option a is a right answer.
4) When a primary alcohol is converted to a carboxylic acid, the terminal carbon atom increases its oxidation state by four.There is involvement of four electron oxidation in reaction. Option d is the right answer.
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