Determine the limiting reactant (LR) and the mass (in g) of nitrogen that can be

Question

Determine the limiting reactant (LR) and the mass (in g) of nitrogen that can be formed from 100.0 g N_2O_4 and 45.0 g N_2H_4. Some possibly useful molar masses are as follows: N_2O_4 = 92.02 g/mol, N_2H_4 = 32.05 g/mol. N_2O_4(l) + 2 N_2H_4(l) rightarrow 3 N_2(g) + 4 H_2O (g) Based on the solubility rules, which of the following will occur if solutions of CuSO_4(aq) and BaCl_2(aq) are mixed? CuCl_2 will precipitate; Ba^2+ and SO_4^2- are spectator ions. CuSO_4 will precipitate; Ba^2+ and Cl^- are spectator ions. BaSO_4 will precipitate; Cu^2+ and Cl^- are spectator ions. BaCl_2 will precipitate; Cu^2+ and SO_4^2- are spectator ions. No precipitate will form. What volume of 0.1409 M NaOH would be required to exactly neutralize 25.00 mL of 0.1713 M H_2SO_4? 2NaOH + H_2SO_4 rightarrow Na_2SO_4 + 2H_2O.

Explanation / Answer

23.
from the given data

H2SO4 + 2 NaOH ------> Na2SO4 + 2H2O

from equation , 1 mole H2SO4 = 2 mole NaOH

NO of mole of H2SO4 = M*v = 25*0.1713 = 4.28 mmole

no of mole of NaOH = M*V = 2*4.28 = 8.56 mmole

volume of NaOH required = n/M = 8.56/0.1409 = 60.75 ml

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