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Take Test Test 4-organic Chomistry 124/2016 4 points I Save Answer UN D The expe

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Question

Take Test Test 4-organic Chomistry 124/2016 4 points I Save Answer UN D The expected Markovnikov addition product of HI to 2-methyl 2-butene is: A. 1-odo-2-methylbutane O B.2-odopentane o C. 1 -odo-3-methylbutane O D. iodo-3-methylbutane 2 E. 2-odo-2-methylbutane QUESTION 7 2 points Save Answer In a reaction where addition and elimination reactions are in equilibrium, which of the following statements is most correct? O A. Addition and elimination reactions are favored at low temperatures. B. Only addition reactions are favored at low temperatures. 0 C. Only elimination reactions are favored at low temperatures. O D. Addition and elimination reactions are disfavored at low temperatures. O E Addition and elimination reactions are favored at high temperatures. Question Completion Status: QUESTION 8 Which of the following is the lUPAC name for the following compound? O A. 3-methylcyclohexene B. 1-methyl-5-cyclohexene C. 2-methylcyclohexenc D. 1-methyl-2-cyclohexene QUESTION 9 2 points Save Answer Which reagents are most likely to accomplish the transfommation shown below? CH 1. BH3-THF 2. Ho H202, H20 O B. H+, H20 o c 1. HgdoAc 2, H20. THF 2. NaBH4 D. 1. Hg (OAc)2, CH30H 2. NaBH4 E. NaOH, H20 QUESTION 10 2 points Save Answer What major product is expected from the following reaction? tizG OH https ont/takellaunch isp?course assessment id 47612 1&course; id 178764 18content id -716829-18ste... 313

Explanation / Answer

question 6: option E is correct. (according to Markonikov's addition of HI to alkene, the nucleophilic part of HI that is I- is attached to more substituted carbon of double bond to form more substituted alkyl halide as major product.)

Question 7: option B is correct (elimination reactions are favoured at high temperatures.)

question 8: option A is correct (A methyl substituent is located at 3rd position and a double bond is located at 1st position so the name is 3-methylcyclohexene.)

question 9: option A is correct (hydroboration - oxidation of alkene with BH3, THf and H2O2, OH- and H2O forms less subtituted alcohol as amjor product.)

question 10: option E is correct (Addition of Br2 and H2O to alkene produces hypohalide having -OH group at more substitued carbon of double bond.)