PLEASEN NOW ASAP For the following reaction, carbon is C(s) + O_2(g) rightarrow

Question

PLEASEN NOW ASAP

For the following reaction, carbon is C(s) + O_2(g) rightarrow CO_2(g) reduced. the electron the oxidizing agent. the electron donor. More than one of the above. A mixture of 6.72 L of H_2 and 11.2 L of He was prepared at STP conditions. Calculate the mole fraction of each gas the mixture at 25 Degree C. H_2: 0.60; H_e: 0.40 H_2: 0.38; H_e: 0.62 H_2: 0.62; H_e: 0.38 H_2: 0.40; H_e: 0.60 None of the above Which one completely of the following is the correct volume of 0.10 M H_2SO_4 needed to react a. with 0.10 L of 0.05 M NaOH? 50 mL 125 mL 25 mL 100 mL None of the above Calculate the sodium ion (Na^+) concentration when 25.0 mL of 0.15 M sodium carbonate solution is added to 50.0 mL 0.030 M potassium chloride solution. 0.05 M 0.10 M 0.12 M 0.30 M None of the above

Explanation / Answer

12)
Oxidation state of C changes from 0 to +4, So it is oxidised. Or in other words it donated its eletrons to oxygen
Answer: d

13)
mole fraction will be directly proportional to volume fraction
for H2 : 6.72 / (6.72 + 11.2) = 0.38
remaining will be He
He: 1-0.38 = 0.62

Answer: b

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