A sample of gas occupies 6.34L at 11°C and 1.00atm. What temperature is needed f

Question

A sample of gas occupies 6.34L at 11°C and 1.00atm. What temperature is needed for the gas to occupy 9.42L at 1.00atm? Need some help please and thank you show step by step
A sample of gas occupies 6.34L at 11°C and 1.00atm. What temperature is needed for the gas to occupy 9.42L at 1.00atm? Need some help please and thank you show step by step
A sample of gas occupies 6.34L at 11°C and 1.00atm. What temperature is needed for the gas to occupy 9.42L at 1.00atm? Need some help please and thank you show step by step
A sample of gas occupies 6.34L at 11°C and 1.00atm. What temperature is needed for the gas to occupy 9.42L at 1.00atm? Need some help please and thank you show step by step

Explanation / Answer

use formula

P1V1/T1 = P2V2/T2

where

P1 = 1 atm, V1 = 6.34 L, T1 = 11ºC convert in to K = 273 + 11 = 284K

P2 = 1 atm, V2 = 9.42 L, T2 = ?

put these values in above equation

1 atm x 6.34 L / 284 K = 1 atm x 9.42 L / T2

T2 = 9.42 L atm x 284 K / 6.34 L

T2 = 421.97 K

= 421.97 - 273 = 148.97 ºC

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