A sample of chromium weighing 564 g was initially at a temperature of 26.45 degr

Question

A sample of chromium weighing 564 g was initially at a temperature of 26.45 degrees C. It required 1207 joules of heat energy to increase the temperature to 30.35 degrees C.
A. What is the specific heat capacity of the chromium? B. What is the molar heat capacity of the chromium? C. What is the heat capacity of the chromium? A sample of chromium weighing 564 g was initially at a temperature of 26.45 degrees C. It required 1207 joules of heat energy to increase the temperature to 30.35 degrees C.
A. What is the specific heat capacity of the chromium? B. What is the molar heat capacity of the chromium? C. What is the heat capacity of the chromium?
A. What is the specific heat capacity of the chromium? B. What is the molar heat capacity of the chromium? C. What is the heat capacity of the chromium?

Explanation / Answer

Q = mcdeltaT

where c= specific heat capacity

c = Q/mdeltaT

c = 1207J/564g.(30.35-26.45)°C

c =1207J/564g*3.9°C

c = 1207J/2199.6gC

c = 0.5487J/gC

Specific heat capacity of chromium = 0.5487J/gC

B.moles of chromium = mass of chromium/molar mass of chromium

= 564g/52g/mol = 10.85moles

Molar heat capacity = specific heat capacity/moles =0.5487J/gC /10.85moles = 0.051J/gCmol

C.Heat capacity = Mass*specific heat capacity

= 564g*0.5487J/gC = 309.5J/C

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