Using the half reaction potentials from table, calculate the E degree_cell for t

Question

Using the half reaction potentials from table, calculate the E degree_cell for the Ni-Al cell. For the Ni-Al cell in question write the following reactions. Cathode Reaction: Anode Reaction Redox Reaction: Using your answer from question 4. determine the E_cell for a Ni-Al cell 4 00 M and the concentration of Al^3+ (aq) is 2.4.00 M and the concentration of Ni^2+ (aq) is 2.00 times 10^- 5 M Using your bench average of the experimental value for E_cell from Part III and the equations on page 9, calculate K_ap for AgCI or CuCO_3

Explanation / Answer

Ni-Al cell representation : Al / Al+3 // Ni+2 / Ni

4 ) E0cell = E 0cathode - E 0anode =[(-0.25)- (-1.66)]=1.41V

5)   Cathode reaction : Ni+2 +2e --> Ni

6) Anode reaction : Al -3e --> Al+3

7) Redox reaction : 2Al +3Ni+2 --> 2Al+3 + 3 Ni

8) According to Nernst equation : E cell = E0cell - (0.059/n) log (Al+3   / Ni+2 )

so, E cell = 1.41- (0.059/6) log (4 / 2 * 10 -5)

      E cell = 1.35V

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