The vapor pressure of liquid methanol, CH3OH, is 100. mm Hg at 294 K. A sample o
ID: 1066015 • Letter: T
Question
The vapor pressure of liquid methanol, CH3OH, is 100. mm Hg at 294 K. A sample of CH3OH is placed in a closed, evacuated 572 mL container at a temperature of 294 K. It is found that all of the CH3OH is in the vapor phase and that the pressure is 50.0 mm Hg. If the volume of the container is reduced to 328 mL at constant temperature, which of the following statements are correct? Choose all that apply.
Only methanol vapor will be present.
The pressure in the container will be 100. mm Hg.
No condensation will occur.
Some of the vapor initially present will condense.
Liquid methanol will be present.
Explanation / Answer
from the boyle s law
P1V1 = P2 V2
P2 = P1 V1 / V2
= ( 50 mmHg * 572 ml ) / 328 ml
= 87.19 mmHg
therefore
the correct statements are:
1) Only methanol vapor will be present.
2) No condensation will occur.
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