The pH of a saturated Cd(OH) 2 solution is 9.46. Match the following to the corr

Question

The pH of a saturated Cd(OH)2 solution is 9.46. Match the following to the correct answer:

A. calculate the concentration of OH -at equilibrium

B. Calculate the concentration of Cd2+at equilibrium

C. Calculate the Ksp of Cd(OH)2

[OH-] =_____________mol/L

[Cd2+] = __________mol/L

Ksp =_______________

1.2 x10-14

1.4 x10-5

2.9 x10-5

3.2 x10-4

      -       A.       B.       C.       D.   

[OH-] =_____________mol/L

      -       A.       B.       C.       D.   

[Cd2+] = __________mol/L

      -       A.       B.       C.       D.   

Ksp =_______________

A.

1.2 x10-14

B.

1.4 x10-5

C.

2.9 x10-5

D.

3.2 x10-4

Explanation / Answer

A) pH = 14 - pOH = 14 +log(OH-) = 9.46

=>-log(OH-) =14-9.46 =4.54

=>OH- = 10^-4.54 =0.0000288 M

1st answer is C

Assume concentration of Cd2+ is x
[Cd2+] = x
Then [OH-] = 2*x =2.9*10^-5

=>x = 1.45*10^-5 M

2nd answer B

Reaction involved in the process

Cd(OH)2 ==> Cd2+ + 2OH-

Then expression for Ksp is given as
Ksp = [Cd2+]*[OH-]^2

Ksp= (1.4*10^-5)*(2*1.4*10^-5)^2
=1.0976*10^-14
Answer is A

Finally C B A

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