11. A student adds o.1 molof oxalic phosphate to enough water to make 1.0 Lof so

Question

11. A student adds o.1 molof oxalic phosphate to enough water to make 1.0 Lof solution. The following equilibrium is established with the about the products greater than the concentrations of the reactants. Which of the statements equilibrium system is correct? Hzczo (aq) H2PO4 (aq) A) Oxalic acid is a weaker acid than phosphoric acid. anion, HaPO B) The hydrogen oxalate anion, Hczo is a stronger base than the dihydrogen phosphate Phosphoric acid is a weaker acid than oxalic acid. D) The dihydrogen phosphate anion, Hapoe is a stronger acid than oxalic acid. E) Water is a stronger acid than either oxalic or phosphoric acids. 12.A solution is adjusted from pH 4 to pH s. The relative concentration of th hydrogen H1 ion has changed by a factor of what? D) 10 E) None of the above C) 5 13. What is the [Ho] for a solution at 25 c that has poH-5.640? A) 2.34 x 10 M B) 2.29 x 10 M C) 4.37 x 109 M D) 4.27 x 10 M E) 8.360 M 14. Which one of the following pairs is not a conjugate acid-base pair? A) H20/oH E) HCl/H' 15. Select the correct relationship among the concentrations of species present in a 1.0 M aqueous solution of the weak acid represented by HA.

Explanation / Answer

Q11

if products > reactants, then H2C2O4 is donating much more H+ to H2PO4-

therefore, H2C2O4 is a stronger acid and H2PO4- acts as a base

a)

false, since it is stronger

b)

false, it won't accept h+ ions readily

c)

true, as stated before

d)

false, stated before

e) false, you can't compare in here,

Q12

pH = 4 --> pH = 5

since this is 10 ^-x

then

x = 1/10

decrease in 10, so choose B

Q13

pH = 14-pOH =14-5.64 = 8.36[H3O+] = 10^-pH = 10^-8.36 = 4.36*10^-9 M

Q14

conjugates...

C)

HCl and H are not pairs... since we are changing the Cl ion... for all other, there is only H+ exchange, so they are good answer

Q15

[H2O] > anythign

for an acid.. [OH] < [H]

and [H+] = [A-] approx

but

[HA] > [H+]

therefore

[H2O] > [HA] > [H+] = [A-] > [H+]

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