The K_sp equilibrium equation is always written for the dissociation of the very

Question

The K_sp equilibrium equation is always written for the dissociation of the very slightly soluble salt. Writhe out the dissociation equations for aluminum hydroxide, copper (II) hydroxide, and zine hydroxide. Obtain the formation constants, K_f for the four soluble complex ions that you observed and reported in the table in question. The K_f equilibrium equation is always written for the formation of the complex ion (see examples in Table 17.4 on page 619.) In the space below, write the formation equilibrium equation for the four soluble complex ions you included above. Which complex ion is the most soluble? The least soluble? How do you know?

Explanation / Answer

8) Ksp expressions

Al(OH)3

Ksp = [Al3+][OH-]^3

Cu(OH)2

Ksp = [Cu2+][OH-]^2

Zn(OH)2

Ksp = [Zn2+][OH-]^2

10) Formation constant

Al(OH)4-

Kf = [Al(OH-]^4/[Al(OH)3][OH-]

[Cu(NH3)4]2+

Kf = [Cu(NH3)4]2+/[Cu(OH)2][NH3]^4

11) complex ion of Cu2+ is most soluble

Followed by Al3+ in basic medium

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